task struct and the #! operator

Hi, I am trying to understand process creation and associated bookkeeping.I am currently trying to understand how interpreted scripts (the shebang operator) are executed. It was surprising to see that the comm member of task_struct (accessed through get_task_comm) is actually set to the name of the script though /proc/pid/exe correctly points to the invoked interpreter. Does anybody know where the necessary magic happen and is it possible to get the name of invoked interpreter through any means inside the kernel? Thanks in advance, Ranjan