Init task 8192 byte alignment query.

Hi I was going through arm vmlinux script file. and i found below statements /* * first, the init task union, aligned * to an 8192 byte boundary. */ INIT_TASK_DATA(THREAD_SIZE) #define INIT_TASK_DATA(align) \ . = ALIGN(align); \ *(.data..init_task) As i know we align data structures on a n byte boundary to save access time and for speed execution but i did not understand why do we need to align this particular data structure on a 8192 byte boundary. sometimes it will be on 1024 or 2048 byte boundary. Any inputs would be appreciated!!! Regards