On Oct 12, 2012 9:36 PM, "Pietro Paolini" <P.Paolini@ext.adbglobal.com> wrote:
Hello,
I am struggling with the byte order question on a x86_32 arch, I am doing
some modifications on a program which actually works fine on a MIPS arch.
I do a reading from a RAW socket in this way:
/* Configure socket */ if ((fd = socket(AF_INET, SOCK_RAW, IPPROTO_IGMP)) < 0) { perror("Error on socket creation, exit"); exit(1); } .... if (setsockopt(fd, IPPROTO_IP, IP_PKTINFO, (void *)&va,
sizeof(va))) {
perror("Error on setsockopt, exit"); exit(1); } va = 0; .... .... struct msghdr mhdr; struct __in_pktinfo *pktinfo = NULL; ... ... nrd = recvmsg(env->mrouter_fd, &mhdr, 0); ... ip = (struct iphdr *)iov.iov_base;
When I print the saddr (or daddr) of the received ip packet it is printed
as host byte order instead of what I am expecting, the network byte order. I can just use the htonl() family functions for solve the problem but I would like understand if it is the normal behavior or if there is an issues on my code, or if the device driver of my NIC can influence the question. I think you should use ntoh*() functions when accessing data rx'ed from the n/w. Network byte order is big endian and your host is little endian, so you'll have convert it to the right order before accessing. You should use hton*() functions when tx'ing data. CMIIW. HTH, -mandeep
Many thanks, Pietro.
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