Guys, I was late to the party. But this whole discussion throughs me off. When you say byte order, it applied when the width of data is more than a byte, lets say our width is 4 bytes, a typical word length. Now how is that there will be byte order on a byte width data. Are you talking about nibble order. When you talk byte order -- either little endian or big endian, we are talking how is our data should be interpreted. Depending on order we start reading data from left or right a byte at a time. So, I am confused on your discussions. Please clarify. Thanks, Sri. On Mon, Feb 20, 2012 at 5:32 PM, THAI NGUYEN <thai-n@rogers.com> wrote:
Just as an FYI, way back in the early '90s, Texas Instruments came out with a graphics processor (I believe the TMS340x0 praphics processor) that actually did do the little-ending and big-endian down to the bit level.
________________________________ From: Subramaniam Appadodharana <c.a.subramaniam@gmail.com> To: Tao Jiang <jiangtao.jit@gmail.com> Cc: Graeme Russ <graeme.russ@gmail.com>; Bernd Petrovitsch <bernd@petrovitsch.priv.at>; Peter Senna Tschudin <peter.senna@gmail.com>; kernelnewbies@kernelnewbies.org Sent: Monday, February 20, 2012 8:53:10 AM Subject: Re: How to figure out the byteorder only with one byte number?
Hi Tao,
On Mon, Feb 20, 2012 at 5:25 AM, Tao Jiang <jiangtao.jit@gmail.com> wrote:
Hi:
Thank you all.
Take a byte number 0b00000001 for example ^ ^ high bit low bit
I used to think in a LE machine it will be stored as 0b10000000 low bit first
^ ^
low bit high bit
and in a BE machine will be 0b00000001 high bit first ^ ^ high bit low bit
not only the byteorder is different, but inside a byte is also different.
But actually they are the same, right? yes they are same. In fact it is termed as 'byte' order not 'bit' order. Hope this helps. Thank you.
2012/2/20 Graeme Russ <graeme.russ@gmail.com>:
On 02/20/2012 01:24 AM, Bernd Petrovitsch wrote:
On Sun, 2012-02-19 at 20:08 +0800, Tao Jiang wrote: [...]
Is there some difference of the storge between BE and LE machine inside a byte?
No. At least TTBOMK there exists no such hardware.
Using SHL/SHR would tell you - SHL normally results in a multiply by 2, SHR a divide by 2. If the byte was little endian, the results would be visa-versa
But I agree, I doubt there is any such hardware
Regards,
Graeme
_______________________________________________ Kernelnewbies mailing list Kernelnewbies@kernelnewbies.org http://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies
_______________________________________________ Kernelnewbies mailing list Kernelnewbies@kernelnewbies.org http://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies
_______________________________________________ Kernelnewbies mailing list Kernelnewbies@kernelnewbies.org http://lists.kernelnewbies.org/mailman/listinfo/kernelnewbies
-- Regards, Sri.