How does module_init(jpeg_init) get called

Jan. 9, 2014

      Hi,

In a kernel driver code, I see it has 'module_init(jpeg_init)' and
'module_exit(jpeg_exit)'.  I would like how know how will
jpeg_init(void) gets call during kernel bring up.

As an example:
static int __init jpeg_init(void)
{
printk(KERN_CRIT "Initialize JPEG driver\n");

platform_driver_register(&jpeg_driver);

return 0;
}

static void __exit jpeg_exit(void)
{
platform_driver_unregister(&jpeg_driver);
}

module_init(jpeg_init);
module_exit(jpeg_exit);

Thank you.

How does module_init(jpeg_init) get called

m silverstri