Jan. 31, 2011
9:42 p.m.
If dummy and dummy2 are of different types, then when you try and do a pointer comparison (&dummy == &dummy2) it will produce a compiler warning/error.
O--ooohhh... I came across this ages ago when I was trying to unravel the jiffies wraparound macros and I've been scratching my head ever since trying to figure out what this line _really_ did. A bit arcane, isn't it? Thanks a lot Dave and everyone for explaining. Cheers Julie