x86 boot gdt

Hello all, Have a little question about gdt initialization. We can see the following: [GDT_ENTRY_BOOT_CS] = GDT_ENTRY(0xc09b, 0, 0xfffff), in the arch/x86/boot/pm.c. Why accessed bit is set here (9b)? I see that it was not set (9a) in the earliest versions. What's reason was to change it? -- _________________________ 0xAX