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Sure. That's a completely different issue. But this works: extern int b; int *a = &b; int b = 20; int main(void) { return 0; } and that's what the code you refer do does.
Sure. That's a completely different issue. But this works:
extern int b; int *a = &b; int b = 20;
int main(void) { return 0; }
and that's what the code you refer do does.
Yes, that make sense, thanks very much :-) -- Rock Lee
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