Jan. 10, 2013
10:09 a.m.
On Thu, Jan 10, 2013 at 9:00 AM, Preeti U Murthy <preeti@linux.vnet.ibm.com> wrote:
d1's 'groups',both the sd0s.Here is the next advantage.It needs information about the sched group alone and will not bother about the individual cpus in it.it checks if load(sd0[cpu2,cpu3]) > load(sd0[cpu0,cpu1]) Only if this is true does it go on to see if cpu2/3 is more loaded.If there were no scheduler domain or groups,we would have to see the states of cpu2 and cpu3 in two iterations instead of 1 iteration like we are doing now.
Thanks Peter and preeti, I had seen that intel link and had read but was not very clear with it, with both explanations and new links I am clear.