Kernel Linked Lists (list_splice)
Jeff Haran
Jeff.Haran at citrix.com
Wed Mar 25 18:18:36 EDT 2015
-----Original Message-----
From: kernelnewbies-bounces at kernelnewbies.org [mailto:kernelnewbies-bounces at kernelnewbies.org] On Behalf Of Leandro M Barbosa
Sent: Wednesday, March 25, 2015 2:41 PM
To: kernelnewbies at kernelnewbies.org
Subject: Re: Kernel Linked Lists (list_splice)
To clarify my doubt, it seems to me that it just sits there in memory without it being referenced anymore, is that right?
On Wed, Mar 25, 2015 at 6:38 PM, Leandro M Barbosa <lbarbosa at linux.com> wrote:
> Hello all!
>
> I was reading the __list_splice () function code and I had a doubt. The code is:
>
> 274 static inline void __list_splice(const struct list_head *list,
> 275 struct list_head *prev,
> 276 struct list_head *next)
> 277 {
> 278 struct list_head *first = list->next;
> 279 struct list_head *last = list->prev;
> 280
> 281 first->prev = prev;
> 282 prev->next = first;
> 283
> 284 last->next = next;
> 285 next->prev = last;
> 286 }
>
> What happens with the *list head? As I understood, when you call
> list_splice (list_a, list_b, list_b->next), the code joins the two
> lists together such that the list_a is put before list_b. The code
> grabs list->next and list->prev but what about *list itself?
>
>
> --
> Leandro Moreira Barbosa
The linked list API represented in list.h allows the creation of linked lists in which a list of structures containing instances of struct list_head can be linked together and anchored by an instance of a struct list_head which is not a member of the structures in the list. Sometimes that anchor is a standalone instance of struct list_head. Other times it's an instance of list_head in another structure, for example:
struct foo {
int data;
struct list_head list;
};
struct bar {
int other_data;
struct list_head foo_list;
};
With the above you'd create a linked list of struct foos that is anchored (or headed) by the foo_list field in an instance of struct bar.
That means that when you splice the list of foos in one instance of bar A to the list of foos in another instance of bar B, you don't want to include the foo_list in the A in the list in B since it's not contained in a foo, but another bar.
This is different than the traditional linked lists that they taught me back in the stone age when I took CS101, but it enables a single object to be included in many lists.
Jeff Haran
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