why is this result ?

[horseriver]

On Sat, Jan 19, 2013 at 09:15:23AM +0100, Jędrzej Dudkiewicz wrote:
> >> Because it's not possible to have an object with nonzero size.  The
> >> address of every object must be unique, so they have to be separated by
> >> one byte anyway.
> >
> >   thanks!
> >   Here I do not define a object of type A ,just do sizeof operation to a A struct ,not a specified object.
> >   So if I defined A a , does  sizeof(a) have the same mean with sizeof(A)  ?
> >   what does the sizeof operator essentially?
> 
> Yes, sizeof(a) and sizeof(A) are identical. I understand sizeof(expr)
> as "tell me how many bytes I need to store result of expression expr"
.
When a is stored in one bytes, what is the mean or use of that byte data?

> -- 
> Jędrzej Dudkiewicz
> 
> I really hate this damn machine, I wish that they would sell it.
> It never does just what I want, but only what I tell it.