How to figure out the byteorder only with one byte number?

[Sri Ram Vemulpali]

Guys,

I was late to the party. But this whole  discussion throughs me off.
When you say byte order, it applied when the width of data is more
than a byte, lets say our width is 4 bytes, a typical word length.

Now how is that there will be byte order on a byte width data. Are you
talking about nibble order.

When you talk byte order -- either little endian or big endian, we are
talking how is our data should be interpreted. Depending on order we
start reading data from left or right a byte at a time.

So, I am confused on your discussions. Please clarify.

Thanks,
Sri.

On Mon, Feb 20, 2012 at 5:32 PM, THAI NGUYEN <thai-n at rogers.com> wrote:
>
> Just as an FYI, way back in the early '90s, Texas Instruments came out with
> a graphics processor (I believe the TMS340x0 praphics processor) that
> actually did do the little-ending and big-endian down to the bit level.
>
>
> ________________________________
> From: Subramaniam Appadodharana <c.a.subramaniam at gmail.com>
> To: Tao Jiang <jiangtao.jit at gmail.com>
> Cc: Graeme Russ <graeme.russ at gmail.com>; Bernd Petrovitsch
> <bernd at petrovitsch.priv.at>; Peter Senna Tschudin <peter.senna at gmail.com>;
> kernelnewbies at kernelnewbies.org
> Sent: Monday, February 20, 2012 8:53:10 AM
> Subject: Re: How to figure out the byteorder only with one byte number?
>
> Hi Tao,
>
>
> On Mon, Feb 20, 2012 at 5:25 AM, Tao Jiang <jiangtao.jit at gmail.com> wrote:
>> Hi:
>>
>> Thank you all.
>>
>> Take a byte number 0b00000001 for example
>>                                     ^             ^
>>                               high bit     low bit
>>
>> I used to think in a LE machine it will be stored as 0b10000000 low bit
>> first
>>
>>            ^             ^
>>
>>        low bit     high bit
>>
>> and in a BE machine will be 0b00000001 high bit first
>>                                                ^             ^
>>                                             high bit    low bit
>>
>> not only the byteorder is different, but inside a byte is also different.
>>
>> But actually they are the same, right?
> yes they are same. In fact it is termed as 'byte' order not 'bit'
> order. Hope this helps.
>> Thank you.
>>
>>
>>
>> 2012/2/20 Graeme Russ <graeme.russ at gmail.com>:
>>> On 02/20/2012 01:24 AM, Bernd Petrovitsch wrote:
>>>> On Sun, 2012-02-19 at 20:08 +0800, Tao Jiang wrote:
>>>> [...]
>>>>> Is there some difference of the storge between BE and LE machine inside
>>>>> a byte?
>>>>
>>>> No. At least TTBOMK there exists no such hardware.
>>>
>>> Using SHL/SHR would tell you - SHL normally results in a multiply by 2,
>>> SHR
>>> a divide by 2. If the byte was little endian, the results would be
>>> visa-versa
>>>
>>> But I agree, I doubt there is any such hardware
>>>
>>> Regards,
>>>
>>> Graeme
>>>
>>
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-- 
Regards,
Sri.