How to figure out the byteorder only with one byte number?

[THAI NGUYEN]

Just as an FYI, way back in the early '90s, Texas Instruments came out with a graphics processor (I believe the TMS340x0 praphics processor) that actually did do the little-ending and big-endian down to the bit level.



________________________________
 From: Subramaniam Appadodharana <c.a.subramaniam at gmail.com>
To: Tao Jiang <jiangtao.jit at gmail.com> 
Cc: Graeme Russ <graeme.russ at gmail.com>; Bernd Petrovitsch <bernd at petrovitsch.priv.at>; Peter Senna Tschudin <peter.senna at gmail.com>; kernelnewbies at kernelnewbies.org 
Sent: Monday, February 20, 2012 8:53:10 AM
Subject: Re: How to figure out the byteorder only with one byte number?
 
Hi Tao,


On Mon, Feb 20, 2012 at 5:25 AM, Tao Jiang <jiangtao.jit at gmail.com> wrote:
> Hi:
>
> Thank you all.
>
> Take a byte number 0b00000001 for example
>                                     ^             ^
>                               high bit     low bit
>
> I used to think in a LE machine it will be stored as 0b10000000 low bit first
>
>            ^             ^
>
>        low bit     high bit
>
> and in a BE machine will be 0b00000001 high bit first
>                                                ^             ^
>                                             high bit    low bit
>
> not only the byteorder is different, but inside a byte is also different.
>
> But actually they are the same, right?
yes they are same. In fact it is termed as 'byte' order not 'bit'
order. Hope this helps.
> Thank you.
>
>
>
> 2012/2/20 Graeme Russ <graeme.russ at gmail.com>:
>> On 02/20/2012 01:24 AM, Bernd Petrovitsch wrote:
>>> On Sun, 2012-02-19 at 20:08 +0800, Tao Jiang wrote:
>>> [...]
>>>> Is there some difference of the storge between BE and LE machine inside a byte?
>>>
>>> No. At least TTBOMK there exists no such hardware.
>>
>> Using SHL/SHR would tell you - SHL normally results in a multiply by 2, SHR
>> a divide by 2. If the byte was little endian, the results would be visa-versa
>>
>> But I agree, I doubt there is any such hardware
>>
>> Regards,
>>
>> Graeme
>>
>
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