Hello everybody, I am tracing the boot kernel process (http://tldp.org/HOWTO/Linux-i386-Boot-Code-HOWTO) and I have a question: GNU/GRUB loads vmlinuz at 0x7c00 memory, does not it? And then, the first instruction CPU executes is in bootsec.S, does not it? Have I understood well? I do not if this is the place for this question. Regards, Román.