Network Byte order not reached reading from a sock RAW
Pietro Paolini
P.Paolini at ext.adbglobal.com
Mon Oct 15 03:46:08 EDT 2012
Hello,
Thanks for your answer, my question is why when I read from the buffer data is already in host byte order and not in network byte order.
Thanks
Pietro Paolini.
From: Mandeep Sandhu [mailto:mandeepsandhu.chd at gmail.com]
Sent: sabato 13 ottobre 2012 05:30
To: Pietro Paolini
Cc: kernelnewbies at kernelnewbies.org
Subject: Re: Network Byte order not reached reading from a sock RAW
On Oct 12, 2012 9:36 PM, "Pietro Paolini" <P.Paolini at ext.adbglobal.com> wrote:
>
> Hello,
>
> I am struggling with the byte order question on a x86_32 arch, I am doing some modifications on a program which actually works fine on a MIPS arch.
>
> I do a reading from a RAW socket in this way:
>
> /* Configure socket */
> if ((fd = socket(AF_INET, SOCK_RAW, IPPROTO_IGMP)) < 0) {
> perror("Error on socket creation, exit");
> exit(1);
> }
> ....
> if (setsockopt(fd, IPPROTO_IP, IP_PKTINFO, (void *)&va, sizeof(va))) {
> perror("Error on setsockopt, exit");
> exit(1);
> }
> va = 0;
> ....
> ....
> struct msghdr mhdr;
> struct __in_pktinfo *pktinfo = NULL;
> ...
> ...
> nrd = recvmsg(env->mrouter_fd, &mhdr, 0);
> ...
> ip = (struct iphdr *)iov.iov_base;
>
> When I print the saddr (or daddr) of the received ip packet it is printed as host byte order instead of what I am expecting, the network byte order. I can just use the htonl() family functions for solve the problem but I would like understand if it is the normal behavior or if there is an issues on my code, or if the device driver of my NIC can influence the question.
I think you should use ntoh*() functions when accessing data rx'ed from the n/w. Network byte order is big endian and your host is little endian, so you'll have convert it to the right order before accessing. You should use hton*() functions when tx'ing data. CMIIW.
HTH,
-mandeep
> Many thanks,
> Pietro.
>
>
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