Hi
I was going through arm vmlinux script file. and i found below statements/** first, the init task union, aligned* to an 8192 byte boundary.*/INIT_TASK_DATA(THREAD_SIZE)#define INIT_TASK_DATA(align) \. = ALIGN(align); \*(.data..init_task)
As i know we align data structures on a n byte boundary to save access timeand for speed execution but i did not understand why do we need to align this particular data structure on a 8192 byte boundary.sometimes it will be on 1024 or 2048 byte boundary.Any inputs would be appreciated!!!
Regards
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