On Thu, Jan 27, 2011 at 13:40, prabhu <prabhum@msys-tech.com> wrote:
No, because 32bit code will tell the datatype size and i think pointer
variable depends on architecture.
So 64 bit processor needs 64 address line to point the data location. So
pointer variable needs to be 8 byte.

Please don't top post and please use the new list address, ok? :)

IMO, I second your opinion. And as addition, I think it's worth to
check /proc/cpuinfo too in "address sizes" field

NB: I was thinking, if in x64, it is operating in full 32 bit mode
(not hybrid one), it is supposed to yield 32 bit address too, right?

--
regards,

Mulyadi Santosa
Freelance Linux trainer and consultant

blog: the-hydra.blogspot.com
training: mulyaditraining.blogspot.com

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I guess a 64bit processor does need 64bit addresses to reference memory. But at the same time, if 32 bit programs are to run unmodified on 64 bit architectures there needs to be ways in which 32bit pointers can still work. So, I am almost 100% sure that compiling 32bit code, even on a 64bit processor, should yield 4 for sizeof(void*)