essentially, when the packet arrive, it will be assigned to the correct process based on IP address + port matching, and then the corresponding process's blocked scheduling status will be changed to continue execution, so that when the scheduler next selection of runnable process will pick him out for continue execution. The process will then pick his data up from the network queue.<div>
<br></div><div>hope I have not made any mistake in my logic?<br><br><div class="gmail_quote">On Tue, Jan 15, 2013 at 8:36 AM, horseriver <span dir="ltr"><<a href="mailto:horserivers@gmail.com" target="_blank">horserivers@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div class="im">On Tue, Jan 15, 2013 at 12:25:10PM -0500, <a href="mailto:Valdis.Kletnieks@vt.edu">Valdis.Kletnieks@vt.edu</a> wrote:<br>
> On Mon, 14 Jan 2013 17:50:03 +0800, horseriver said:<br>
><br>
> > When one datagram has reached , How to wake_up the wait_queue of that socket ?<br>
><br>
> Please clarify your question - I'm not sure which of the following you mean:<br>
><br>
1) How does the kernel wake up the waiting process when a datagram<br>
arrives?<br>
<br>
</div> This is my mean !<br>
<br>
Thanks<br>
<div class="HOEnZb"><div class="h5"><br>
<br>
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</div></div></blockquote></div><br><br clear="all"><div><br></div>-- <br>Regards,<br>Peter Teoh
</div>