Init task 8192 byte alignment query.

[tech learner]

Because L1 cache is 8k deep.

On Wed, Jun 29, 2016 at 10:31 PM, Shiva Shankar <klshiva4a4 at gmail.com>
wrote:

> Hi
> I was going through arm vmlinux script file. and i found  below statements
>
> /*
> * first, the init task union, aligned
> * to an 8192 byte boundary.
> */
>
>  INIT_TASK_DATA(THREAD_SIZE)
>
> #define INIT_TASK_DATA(align) \
> . = ALIGN(align); \
> *(.data..init_task)
>
> As i know we align data structures on a n byte boundary to save access time
> and for speed execution but i did not understand why do we need to align
> this particular data structure on a 8192 byte boundary.
>
> sometimes it will be on 1024 or 2048 byte boundary.
>
> Any inputs would be appreciated!!!
>
> Regards
>
>
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