question about kref API
Greg KH
greg at kroah.com
Mon Jul 21 22:18:19 EDT 2014
On Tue, Jul 22, 2014 at 12:27:20AM +0000, Jeff Haran wrote:
> Hi,
>
> I've been reading Documentation/kref.txt in order to understand the
> usage of this API. There is part of this documentation that I am
> having difficulty understanding and was hoping somebody on this list
> could clarify this. One of my assumptions in reading this is that the
> expected usage of this API is that for a given object embedding a
> kref, once the object has been initialized the number of calls to
> "put" a given instance of an object should never exceed the number of
> calls to "get" that same instance.
If it does, the object will be cleaned up and deleted from the system,
so you no longer have a valid pointer.
> Maybe that's the root of my misunderstanding, but my assumption is
> that calls to kref_get() and kref_put() are expected to be made in
> pairs for a given instance of struct kref. If this is wrong, please
> let me know.
"pairs" in that the same number must be called in order for things to
work properly.
> Kref.txt includes some sample code that discusses using a mutex to
> serialize the execution of its get_entry() and put_entry() functions:
>
> 146 static DEFINE_MUTEX(mutex);
> 147 static LIST_HEAD(q);
> 148 struct my_data
> 149 {
> 150 struct kref refcount;
> 151 struct list_head link;
> 152 };
> 153
> 154 static struct my_data *get_entry()
> 155 {
> 156 struct my_data *entry = NULL;
> 157 mutex_lock(&mutex);
> 158 if (!list_empty(&q)) {
> 159 entry = container_of(q.next, struct my_data, link);
> 160 kref_get(&entry->refcount);
> 161 }
> 162 mutex_unlock(&mutex);
> 163 return entry;
> 164 }
> 165
> 166 static void release_entry(struct kref *ref)
> 167 {
> 168 struct my_data *entry = container_of(ref, struct my_data, refcount);
> 169
> 170 list_del(&entry->link);
> 171 kfree(entry);
> 172 }
> 173
> 174 static void put_entry(struct my_data *entry)
> 175 {
> 176 mutex_lock(&mutex);
> 177 kref_put(&entry->refcount, release_entry);
> 178 mutex_unlock(&mutex);
> 179 }
>
> The sample code does not show the creation of the link list headed by
> q,
That is done there in the static initializer.
> so it is unclear to me what the value of the reference counts in
> these my_data structures are at the time they are enqueued to the
> list. Put another way, it's not clear to me from reading this whether
> kref_init(&(entry->refcount)) was called before the instances of
> struct my_data were put into the list.
Yes it was.
> So I have two interpretations of what is being illustrated with this
> sample code and neither makes much sense to me.
>
> 1) The krefs are initialized before they go into the list.
Yes.
> If the krefs in the instances of struct my_data are initialized by
> kref_init() before they go into the list and thus start off with a 1,
> then it would seem to me that the mutex would not be necessary so long
> as the number of calls to put_entry() never exceeds the number of
> calls to get_entry().
The mutex is needed as multiple threads could be calling kref_put at the
same time if you don't have that.
Best thing is, don't use the "raw" kref_put() calls, use the
kref_put_mutex() or kref_put_spinlock_irqsave() call instead. It's much
easier that way and arguably, I should have done that when I created the
API over a decade ago.
> 2) The krefs are not initialized before they go into the list.
Not true, that will not work.
Look at the users of kref in the kernel, they have to be initialized
before anyone else can ever "touch" them, it's that simple.
What were you looking to use a kref for?
Hope this helps,
greg k-h
More information about the Kernelnewbies
mailing list