typecheck code

julie Sullivan kernelmail.jms at gmail.com
Mon Jan 31 16:42:47 EST 2011

>If dummy and dummy2 are of different types, then when you try and do a
>pointer comparison (&dummy == &dummy2) it will produce a compiler

I came across this ages ago when I was trying to unravel the jiffies
wraparound macros and I've been scratching my head ever since trying
to figure out what this line _really_  did. A bit arcane, isn't it?
Thanks a lot Dave and everyone for explaining.


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